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150156732146437 is a prime number
BaseRepresentation
bin100010001001000100010110…
…101011100010001100000101
3201200122211202211122210002001
4202021010112223202030011
5124140131441412141222
61251205014521545301
743425315542052622
oct4211042653421405
9650584684583061
10150156732146437
114393212679a6a5
1214a11469945231
1365a2946a9a473
1429118a5d21349
151255dc4068e27
hex889116ae2305

150156732146437 has 2 divisors, whose sum is σ = 150156732146438. Its totient is φ = 150156732146436.

The previous prime is 150156732146429. The next prime is 150156732146459. The reversal of 150156732146437 is 734641237651051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 142067662377796 + 8089069768641 = 11919214^2 + 2844129^2 .

It is a cyclic number.

It is not a de Polignac number, because 150156732146437 - 23 = 150156732146429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150156732146497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75078366073218 + 75078366073219.

It is an arithmetic number, because the mean of its divisors is an integer number (75078366073219).

Almost surely, 2150156732146437 is an apocalyptic number.

It is an amenable number.

150156732146437 is a deficient number, since it is larger than the sum of its proper divisors (1).

150156732146437 is an equidigital number, since it uses as much as digits as its factorization.

150156732146437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12700800, while the sum is 55.

Adding to 150156732146437 its reverse (734641237651051), we get a palindrome (884797969797488).

The spelling of 150156732146437 in words is "one hundred fifty trillion, one hundred fifty-six billion, seven hundred thirty-two million, one hundred forty-six thousand, four hundred thirty-seven".