Base | Representation |
---|---|
bin | 1000101111100101010… |
… | …1100000110001111111 |
3 | 112100201112110222110201 |
4 | 2023321111200301333 |
5 | 4430113241213033 |
6 | 153001221344331 |
7 | 13565252251624 |
oct | 2137125406177 |
9 | 470645428421 |
10 | 150212054143 |
11 | 58782874608 |
12 | 251418680a7 |
13 | 1121b497298 |
14 | 73ad9d034b |
15 | 3d9251a47d |
hex | 22f9560c7f |
150212054143 has 2 divisors, whose sum is σ = 150212054144. Its totient is φ = 150212054142.
The previous prime is 150212054131. The next prime is 150212054257. The reversal of 150212054143 is 341450212051.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150212054143 - 29 = 150212053631 is a prime.
It is a super-2 number, since 2×1502120541432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150212054543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75106027071 + 75106027072.
It is an arithmetic number, because the mean of its divisors is an integer number (75106027072).
Almost surely, 2150212054143 is an apocalyptic number.
150212054143 is a deficient number, since it is larger than the sum of its proper divisors (1).
150212054143 is an equidigital number, since it uses as much as digits as its factorization.
150212054143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 150212054143 its reverse (341450212051), we get a palindrome (491662266194).
The spelling of 150212054143 in words is "one hundred fifty billion, two hundred twelve million, fifty-four thousand, one hundred forty-three".
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