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150355121252333 is a prime number
BaseRepresentation
bin100010001011111101000111…
…100101111010011111101101
3201201100210211220202120021212
4202023331013211322133231
5124201404242020033313
61251440104505004205
743445541032454434
oct4213750745723755
9651323756676255
10150355121252333
11439a9281219258
1214a439b5a83665
1365b857243b05a
14291b3260b411b
15125b135d8b3a8
hex88bf4797a7ed

150355121252333 has 2 divisors, whose sum is σ = 150355121252334. Its totient is φ = 150355121252332.

The previous prime is 150355121252197. The next prime is 150355121252377. The reversal of 150355121252333 is 333252121553051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95120170243849 + 55234951008484 = 9752957^2 + 7432022^2 .

It is a cyclic number.

It is not a de Polignac number, because 150355121252333 - 218 = 150355120990189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150355121252393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75177560626166 + 75177560626167.

It is an arithmetic number, because the mean of its divisors is an integer number (75177560626167).

Almost surely, 2150355121252333 is an apocalyptic number.

It is an amenable number.

150355121252333 is a deficient number, since it is larger than the sum of its proper divisors (1).

150355121252333 is an equidigital number, since it uses as much as digits as its factorization.

150355121252333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405000, while the sum is 41.

The spelling of 150355121252333 in words is "one hundred fifty trillion, three hundred fifty-five billion, one hundred twenty-one million, two hundred fifty-two thousand, three hundred thirty-three".