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15040354423 is a prime number
BaseRepresentation
bin11100000000111100…
…11001100001110111
31102211012002011112211
432000132121201313
5221300312320143
610524234554251
71041466621543
oct160036314167
942735064484
1015040354423
116418984986
122ab8b98987
131559008003
14a2972aa23
155d063649d
hex380799877

15040354423 has 2 divisors, whose sum is σ = 15040354424. Its totient is φ = 15040354422.

The previous prime is 15040354411. The next prime is 15040354453. The reversal of 15040354423 is 32445304051.

15040354423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 15040354423 - 25 = 15040354391 is a prime.

It is a super-2 number, since 2×150403544232 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15040354453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7520177211 + 7520177212.

It is an arithmetic number, because the mean of its divisors is an integer number (7520177212).

Almost surely, 215040354423 is an apocalyptic number.

15040354423 is a deficient number, since it is larger than the sum of its proper divisors (1).

15040354423 is an equidigital number, since it uses as much as digits as its factorization.

15040354423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 15040354423 its reverse (32445304051), we get a palindrome (47485658474).

The spelling of 15040354423 in words is "fifteen billion, forty million, three hundred fifty-four thousand, four hundred twenty-three".