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150421624231 is a prime number
BaseRepresentation
bin1000110000010111010…
…0111101010110100111
3112101021010211020120211
42030011310331112213
54431030413433411
6153034105240251
713603405465264
oct2140564752647
9471233736524
10150421624231
11588800a372a
122519ba93087
1311252a22558
1473cd78426b
153da5b15221
hex2305d3d5a7

150421624231 has 2 divisors, whose sum is σ = 150421624232. Its totient is φ = 150421624230.

The previous prime is 150421624207. The next prime is 150421624253. The reversal of 150421624231 is 132426124051.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150421624231 is a prime.

It is a super-2 number, since 2×1504216242312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 150421624193 and 150421624202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150421624271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75210812115 + 75210812116.

It is an arithmetic number, because the mean of its divisors is an integer number (75210812116).

Almost surely, 2150421624231 is an apocalyptic number.

150421624231 is a deficient number, since it is larger than the sum of its proper divisors (1).

150421624231 is an equidigital number, since it uses as much as digits as its factorization.

150421624231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 150421624231 its reverse (132426124051), we get a palindrome (282847748282).

The spelling of 150421624231 in words is "one hundred fifty billion, four hundred twenty-one million, six hundred twenty-four thousand, two hundred thirty-one".