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15046552133 is a prime number
BaseRepresentation
bin11100000001101100…
…00010101001000101
31102211121202001012122
432000312002221011
5221303404132013
610525015455325
71041603403634
oct160066025105
942747661178
1015046552133
116421428358
122abb087545
13155a397cb2
14a2a4a151b
155d0e5ca08
hex380d82a45

15046552133 has 2 divisors, whose sum is σ = 15046552134. Its totient is φ = 15046552132.

The previous prime is 15046552121. The next prime is 15046552139. The reversal of 15046552133 is 33125564051.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12728803684 + 2317748449 = 112822^2 + 48143^2 .

It is a cyclic number.

It is not a de Polignac number, because 15046552133 - 216 = 15046486597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15046552093 and 15046552102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15046552139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7523276066 + 7523276067.

It is an arithmetic number, because the mean of its divisors is an integer number (7523276067).

Almost surely, 215046552133 is an apocalyptic number.

It is an amenable number.

15046552133 is a deficient number, since it is larger than the sum of its proper divisors (1).

15046552133 is an equidigital number, since it uses as much as digits as its factorization.

15046552133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 15046552133 in words is "fifteen billion, forty-six million, five hundred fifty-two thousand, one hundred thirty-three".