Base | Representation |
---|---|
bin | 1000110000110100010… |
… | …1001101001101101101 |
3 | 112101120121211020022011 |
4 | 2030031011031031231 |
5 | 4431303042332023 |
6 | 153054133521221 |
7 | 13606414066165 |
oct | 2141505151555 |
9 | 471517736264 |
10 | 150543324013 |
11 | 58932866565 |
12 | 252147a3211 |
13 | 11271cc3064 |
14 | 74019c35a5 |
15 | 3db165450d |
hex | 230d14d36d |
150543324013 has 2 divisors, whose sum is σ = 150543324014. Its totient is φ = 150543324012.
The previous prime is 150543323989. The next prime is 150543324097. The reversal of 150543324013 is 310423345051.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 150452445924 + 90878089 = 387882^2 + 9533^2 .
It is an emirp because it is prime and its reverse (310423345051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150543324013 - 233 = 141953389421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150543324313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75271662006 + 75271662007.
It is an arithmetic number, because the mean of its divisors is an integer number (75271662007).
Almost surely, 2150543324013 is an apocalyptic number.
It is an amenable number.
150543324013 is a deficient number, since it is larger than the sum of its proper divisors (1).
150543324013 is an equidigital number, since it uses as much as digits as its factorization.
150543324013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 150543324013 its reverse (310423345051), we get a palindrome (460966669064).
The spelling of 150543324013 in words is "one hundred fifty billion, five hundred forty-three million, three hundred twenty-four thousand, thirteen".
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