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150545125433 is a prime number
BaseRepresentation
bin1000110000110100110…
…0000101000000111001
3112101120202012202101102
42030031030011000321
54431304023003213
6153054240301145
713606435311143
oct2141514050071
9471522182342
10150545125433
1158933886a3a
12252153117b5
13112724a3ca1
147401d31c93
153db18ad158
hex230d305039

150545125433 has 2 divisors, whose sum is σ = 150545125434. Its totient is φ = 150545125432.

The previous prime is 150545125429. The next prime is 150545125499. The reversal of 150545125433 is 334521545051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 150429949609 + 115175824 = 387853^2 + 10732^2 .

It is an emirp because it is prime and its reverse (334521545051) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 150545125433 - 22 = 150545125429 is a prime.

It is not a weakly prime, because it can be changed into another prime (150545125403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75272562716 + 75272562717.

It is an arithmetic number, because the mean of its divisors is an integer number (75272562717).

Almost surely, 2150545125433 is an apocalyptic number.

It is an amenable number.

150545125433 is a deficient number, since it is larger than the sum of its proper divisors (1).

150545125433 is an equidigital number, since it uses as much as digits as its factorization.

150545125433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 38.

The spelling of 150545125433 in words is "one hundred fifty billion, five hundred forty-five million, one hundred twenty-five thousand, four hundred thirty-three".