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150807433121 is a prime number
BaseRepresentation
bin1000110001110011010…
…0101100111110100001
3112102021000210100212222
42030130310230332201
54432323200324441
6153140250400425
713616102013452
oct2143464547641
9472230710788
10150807433121
1158a58956654
1225289130115
13112b4935737
147428ad3129
153dc9923d4b
hex231cd2cfa1

150807433121 has 2 divisors, whose sum is σ = 150807433122. Its totient is φ = 150807433120.

The previous prime is 150807433111. The next prime is 150807433123. The reversal of 150807433121 is 121334708051.

150807433121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126067603600 + 24739829521 = 355060^2 + 157289^2 .

It is a cyclic number.

It is not a de Polignac number, because 150807433121 - 214 = 150807416737 is a prime.

Together with 150807433123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (150807433123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75403716560 + 75403716561.

It is an arithmetic number, because the mean of its divisors is an integer number (75403716561).

Almost surely, 2150807433121 is an apocalyptic number.

It is an amenable number.

150807433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

150807433121 is an equidigital number, since it uses as much as digits as its factorization.

150807433121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 35.

The spelling of 150807433121 in words is "one hundred fifty billion, eight hundred seven million, four hundred thirty-three thousand, one hundred twenty-one".