Base | Representation |
---|---|
bin | 1000110010100011101… |
… | …1100100100101111101 |
3 | 112102210012000022002211 |
4 | 2030220323210211331 |
5 | 4433232200413011 |
6 | 153212344220421 |
7 | 13624116404302 |
oct | 2145073444575 |
9 | 472705008084 |
10 | 151010560381 |
11 | 5905258511a |
12 | 2532516a711 |
13 | 11317a46295 |
14 | 7447a8b0a9 |
15 | 3ddc699b21 |
hex | 2328ee497d |
151010560381 has 2 divisors, whose sum is σ = 151010560382. Its totient is φ = 151010560380.
The previous prime is 151010560301. The next prime is 151010560429. The reversal of 151010560381 is 183065010151.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 135243740025 + 15766820356 = 367755^2 + 125566^2 .
It is a cyclic number.
It is not a de Polignac number, because 151010560381 - 211 = 151010558333 is a prime.
It is a super-2 number, since 2×1510105603812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151010560301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75505280190 + 75505280191.
It is an arithmetic number, because the mean of its divisors is an integer number (75505280191).
Almost surely, 2151010560381 is an apocalyptic number.
It is an amenable number.
151010560381 is a deficient number, since it is larger than the sum of its proper divisors (1).
151010560381 is an equidigital number, since it uses as much as digits as its factorization.
151010560381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 31.
The spelling of 151010560381 in words is "one hundred fifty-one billion, ten million, five hundred sixty thousand, three hundred eighty-one".
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