Base | Representation |
---|---|
bin | 1000110010100011111… |
… | …1001011101110111100 |
3 | 112102210020210101210200 |
4 | 2030220333023232330 |
5 | 4433232421212012 |
6 | 153212420403500 |
7 | 13624130426433 |
oct | 2145077135674 |
9 | 472706711720 |
10 | 151011507132 |
11 | 59053071462 |
12 | 25325546590 |
13 | 11317cb81a5 |
14 | 7447c5611a |
15 | 3ddc7d53dc |
hex | 2328fcbbbc |
151011507132 has 36 divisors (see below), whose sum is σ = 384065409000. Its totient is φ = 50028350112.
The previous prime is 151011507103. The next prime is 151011507149. The reversal of 151011507132 is 231705110151.
151011507132 is a `hidden beast` number, since 1 + 5 + 10 + 11 + 507 + 132 = 666.
It is a tau number, because it is divible by the number of its divisors (36).
It is a junction number, because it is equal to n+sod(n) for n = 151011507096 and 151011507105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12861507 + ... + 12873242.
Almost surely, 2151011507132 is an apocalyptic number.
151011507132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
151011507132 is an abundant number, since it is smaller than the sum of its proper divisors (233053901868).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
151011507132 is a wasteful number, since it uses less digits than its factorization.
151011507132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25734922 (or 25734917 counting only the distinct ones).
The product of its (nonzero) digits is 1050, while the sum is 27.
Adding to 151011507132 its reverse (231705110151), we get a palindrome (382716617283).
The spelling of 151011507132 in words is "one hundred fifty-one billion, eleven million, five hundred seven thousand, one hundred thirty-two".
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