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151012510309 is a prime number
BaseRepresentation
bin1000110010100100001…
…1000000101001100101
3112102210022200100220101
42030221003000221211
54433233200312214
6153212454104101
713624142105233
oct2145103005145
9472708610811
10151012510309
1159053697131
122532594b031
131131827999b
147448037953
153ddc932774
hex23290c0a65

151012510309 has 2 divisors, whose sum is σ = 151012510310. Its totient is φ = 151012510308.

The previous prime is 151012510193. The next prime is 151012510333. The reversal of 151012510309 is 903015210151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 150619281409 + 393228900 = 388097^2 + 19830^2 .

It is an emirp because it is prime and its reverse (903015210151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 151012510309 - 233 = 142422575717 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (151012510339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75506255154 + 75506255155.

It is an arithmetic number, because the mean of its divisors is an integer number (75506255155).

Almost surely, 2151012510309 is an apocalyptic number.

It is an amenable number.

151012510309 is a deficient number, since it is larger than the sum of its proper divisors (1).

151012510309 is an equidigital number, since it uses as much as digits as its factorization.

151012510309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350, while the sum is 28.

The spelling of 151012510309 in words is "one hundred fifty-one billion, twelve million, five hundred ten thousand, three hundred nine".