Base | Representation |
---|---|
bin | 1101101111000111100011… |
… | …1000010110100101101011 |
3 | 1222110211211022101012211012 |
4 | 3123301320320112211223 |
5 | 3434422204030114433 |
6 | 52042141124454135 |
7 | 3116110500520226 |
oct | 333617070264553 |
9 | 58424738335735 |
10 | 15103133051243 |
11 | 48a3225962426 |
12 | 183b10884a34b |
13 | 8572b0b59ca3 |
14 | 3a2dd1a945bd |
15 | 1b2d01975848 |
hex | dbc78e1696b |
15103133051243 has 2 divisors, whose sum is σ = 15103133051244. Its totient is φ = 15103133051242.
The previous prime is 15103133051207. The next prime is 15103133051249. The reversal of 15103133051243 is 34215033130151.
It is a strong prime.
It is an emirp because it is prime and its reverse (34215033130151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15103133051243 - 212 = 15103133047147 is a prime.
It is not a weakly prime, because it can be changed into another prime (15103133051249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7551566525621 + 7551566525622.
It is an arithmetic number, because the mean of its divisors is an integer number (7551566525622).
Almost surely, 215103133051243 is an apocalyptic number.
15103133051243 is a deficient number, since it is larger than the sum of its proper divisors (1).
15103133051243 is an equidigital number, since it uses as much as digits as its factorization.
15103133051243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 32.
Adding to 15103133051243 its reverse (34215033130151), we get a palindrome (49318166181394).
The spelling of 15103133051243 in words is "fifteen trillion, one hundred three billion, one hundred thirty-three million, fifty-one thousand, two hundred forty-three".
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