Base | Representation |
---|---|
bin | 100010010101111100111100… |
… | …000001111011000011011111 |
3 | 201210210111010011221022202122 |
4 | 202111330330001323003133 |
5 | 124244133231220113143 |
6 | 1253123443140013155 |
7 | 43546301405664413 |
oct | 4225747401730337 |
9 | 653714104838678 |
10 | 151042122035423 |
11 | 44143671257883 |
12 | 14b34b850911bb |
13 | 663829871b868 |
14 | 2942698bb4d43 |
15 | 126de43ae8c68 |
hex | 895f3c07b0df |
151042122035423 has 2 divisors, whose sum is σ = 151042122035424. Its totient is φ = 151042122035422.
The previous prime is 151042122035419. The next prime is 151042122035443. The reversal of 151042122035423 is 324530221240151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 151042122035423 - 22 = 151042122035419 is a prime.
It is a super-2 number, since 2×1510421220354232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151042122035443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75521061017711 + 75521061017712.
It is an arithmetic number, because the mean of its divisors is an integer number (75521061017712).
Almost surely, 2151042122035423 is an apocalyptic number.
151042122035423 is a deficient number, since it is larger than the sum of its proper divisors (1).
151042122035423 is an equidigital number, since it uses as much as digits as its factorization.
151042122035423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 151042122035423 its reverse (324530221240151), we get a palindrome (475572343275574).
The spelling of 151042122035423 in words is "one hundred fifty-one trillion, forty-two billion, one hundred twenty-two million, thirty-five thousand, four hundred twenty-three".
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