Base | Representation |
---|---|
bin | 1000110011000000101… |
… | …1010111110111111101 |
3 | 112110002122210100020112 |
4 | 2030300023113313331 |
5 | 4434004312034401 |
6 | 153232410155405 |
7 | 13630124010002 |
oct | 2146013276775 |
9 | 473078710215 |
10 | 151132143101 |
11 | 59105178005 |
12 | 25359a22b65 |
13 | 11336ca5714 |
14 | 7459c998a9 |
15 | 3de81b43bb |
hex | 23302d7dfd |
151132143101 has 2 divisors, whose sum is σ = 151132143102. Its totient is φ = 151132143100.
The previous prime is 151132143067. The next prime is 151132143179. The reversal of 151132143101 is 101341231151.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 149854152100 + 1277991001 = 387110^2 + 35749^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-151132143101 is a prime.
It is a super-2 number, since 2×1511321431012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151132143401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75566071550 + 75566071551.
It is an arithmetic number, because the mean of its divisors is an integer number (75566071551).
Almost surely, 2151132143101 is an apocalyptic number.
It is an amenable number.
151132143101 is a deficient number, since it is larger than the sum of its proper divisors (1).
151132143101 is an equidigital number, since it uses as much as digits as its factorization.
151132143101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360, while the sum is 23.
Adding to 151132143101 its reverse (101341231151), we get a palindrome (252473374252).
The spelling of 151132143101 in words is "one hundred fifty-one billion, one hundred thirty-two million, one hundred forty-three thousand, one hundred one".
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