Base | Representation |
---|---|
bin | 1000110011000001000… |
… | …0101101101011000011 |
3 | 112110002202102110200121 |
4 | 2030300100231223003 |
5 | 4434010141334412 |
6 | 153232500201111 |
7 | 13630141630441 |
oct | 2146020555303 |
9 | 473082373617 |
10 | 151133543107 |
11 | 59105a43938 |
12 | 2535a399197 |
13 | 11337375a21 |
14 | 745a141b91 |
15 | 3de838e107 |
hex | 233042dac3 |
151133543107 has 2 divisors, whose sum is σ = 151133543108. Its totient is φ = 151133543106.
The previous prime is 151133543081. The next prime is 151133543137. The reversal of 151133543107 is 701345331151.
It is a weak prime.
It is an emirp because it is prime and its reverse (701345331151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 151133543107 - 27 = 151133542979 is a prime.
It is not a weakly prime, because it can be changed into another prime (151133543137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75566771553 + 75566771554.
It is an arithmetic number, because the mean of its divisors is an integer number (75566771554).
Almost surely, 2151133543107 is an apocalyptic number.
151133543107 is a deficient number, since it is larger than the sum of its proper divisors (1).
151133543107 is an equidigital number, since it uses as much as digits as its factorization.
151133543107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18900, while the sum is 34.
Adding to 151133543107 its reverse (701345331151), we get a palindrome (852478874258).
The spelling of 151133543107 in words is "one hundred fifty-one billion, one hundred thirty-three million, five hundred forty-three thousand, one hundred seven".
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