Base | Representation |
---|---|
bin | 11100001001101110… |
… | …10110101101101001 |
3 | 1110000022200000122001 |
4 | 32010313112231221 |
5 | 221423141132403 |
6 | 10535425331001 |
7 | 1043352632356 |
oct | 160467265551 |
9 | 43008600561 |
10 | 15114005353 |
11 | 6456509a17 |
12 | 2b19796a61 |
13 | 156b354545 |
14 | a3541d62d |
15 | 5d6d33c1d |
hex | 384dd6b69 |
15114005353 has 2 divisors, whose sum is σ = 15114005354. Its totient is φ = 15114005352.
The previous prime is 15114005351. The next prime is 15114005383. The reversal of 15114005353 is 35350041151.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8860833424 + 6253171929 = 94132^2 + 79077^2 .
It is a cyclic number.
It is not a de Polignac number, because 15114005353 - 21 = 15114005351 is a prime.
Together with 15114005351, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (15114005351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7557002676 + 7557002677.
It is an arithmetic number, because the mean of its divisors is an integer number (7557002677).
Almost surely, 215114005353 is an apocalyptic number.
It is an amenable number.
15114005353 is a deficient number, since it is larger than the sum of its proper divisors (1).
15114005353 is an equidigital number, since it uses as much as digits as its factorization.
15114005353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500, while the sum is 28.
The spelling of 15114005353 in words is "fifteen billion, one hundred fourteen million, five thousand, three hundred fifty-three".
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