Base | Representation |
---|---|
bin | 11100001001101111… |
… | …10001000101111001 |
3 | 1110000022212111211211 |
4 | 32010313301011321 |
5 | 221423203112101 |
6 | 10535431523121 |
7 | 1043353562362 |
oct | 160467610571 |
9 | 43008774754 |
10 | 15114113401 |
11 | 6456583112 |
12 | 2b198294a1 |
13 | 156b39178a |
14 | a3544ab69 |
15 | 5d6d55c51 |
hex | 384df1179 |
15114113401 has 2 divisors, whose sum is σ = 15114113402. Its totient is φ = 15114113400.
The previous prime is 15114113393. The next prime is 15114113423. The reversal of 15114113401 is 10431141151.
It is an a-pointer prime, because the next prime (15114113423) can be obtained adding 15114113401 to its sum of digits (22).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13340019001 + 1774094400 = 115499^2 + 42120^2 .
It is a cyclic number.
It is not a de Polignac number, because 15114113401 - 23 = 15114113393 is a prime.
It is not a weakly prime, because it can be changed into another prime (15114113471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7557056700 + 7557056701.
It is an arithmetic number, because the mean of its divisors is an integer number (7557056701).
Almost surely, 215114113401 is an apocalyptic number.
It is an amenable number.
15114113401 is a deficient number, since it is larger than the sum of its proper divisors (1).
15114113401 is an equidigital number, since it uses as much as digits as its factorization.
15114113401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 15114113401 its reverse (10431141151), we get a palindrome (25545254552).
The spelling of 15114113401 in words is "fifteen billion, one hundred fourteen million, one hundred thirteen thousand, four hundred one".
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