Base | Representation |
---|---|
bin | 100010010111011001010011… |
… | …011111111111100111011001 |
3 | 201211010222010001212002021221 |
4 | 202113121103133333213121 |
5 | 124302244340302322301 |
6 | 1253241204340532041 |
7 | 43556412212066260 |
oct | 4227312337774731 |
9 | 654128101762257 |
10 | 151141300042201 |
11 | 441817356a0237 |
12 | 14b502436b1021 |
13 | 6644742b47981 |
14 | 29473c69c35d7 |
15 | 12717eaab4da1 |
hex | 8976537ff9d9 |
151141300042201 has 32 divisors (see below), whose sum is σ = 186378338764800. Its totient is φ = 119661024366720.
The previous prime is 151141300042193. The next prime is 151141300042211. The reversal of 151141300042201 is 102240003141151.
It is a happy number.
It is not a de Polignac number, because 151141300042201 - 23 = 151141300042193 is a prime.
It is not an unprimeable number, because it can be changed into a prime (151141300042211) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 388155 + ... + 17390608.
It is an arithmetic number, because the mean of its divisors is an integer number (5824323086400).
Almost surely, 2151141300042201 is an apocalyptic number.
It is an amenable number.
151141300042201 is a deficient number, since it is larger than the sum of its proper divisors (35237038722599).
151141300042201 is a wasteful number, since it uses less digits than its factorization.
151141300042201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17780389.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 151141300042201 its reverse (102240003141151), we get a palindrome (253381303183352).
The spelling of 151141300042201 in words is "one hundred fifty-one trillion, one hundred forty-one billion, three hundred million, forty-two thousand, two hundred one".
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