Base | Representation |
---|---|
bin | 1101101111110000110101… |
… | …0111000001000010110111 |
3 | 1222111220102120020101020111 |
4 | 3123330031113001002313 |
5 | 3440112402244131043 |
6 | 52051212445043451 |
7 | 3116652212465032 |
oct | 333741527010267 |
9 | 58456376211214 |
10 | 15114214052023 |
11 | 48a79a1895309 |
12 | 184129b856587 |
13 | 8583587a5398 |
14 | 3a376360c019 |
15 | 1b324e6b509d |
hex | dbf0d5c10b7 |
15114214052023 has 2 divisors, whose sum is σ = 15114214052024. Its totient is φ = 15114214052022.
The previous prime is 15114214052011. The next prime is 15114214052057. The reversal of 15114214052023 is 32025041241151.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15114214052023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15114214052423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7557107026011 + 7557107026012.
It is an arithmetic number, because the mean of its divisors is an integer number (7557107026012).
Almost surely, 215114214052023 is an apocalyptic number.
15114214052023 is a deficient number, since it is larger than the sum of its proper divisors (1).
15114214052023 is an equidigital number, since it uses as much as digits as its factorization.
15114214052023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 15114214052023 its reverse (32025041241151), we get a palindrome (47139255293174).
The spelling of 15114214052023 in words is "fifteen trillion, one hundred fourteen billion, two hundred fourteen million, fifty-two thousand, twenty-three".
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