Base | Representation |
---|---|
bin | 1101110000000110011111… |
… | …0000001010011001000001 |
3 | 1222112110102120121121100102 |
4 | 3130001213300022121001 |
5 | 3440211303020420031 |
6 | 52054013245532145 |
7 | 3120246220500611 |
oct | 334014760123101 |
9 | 58473376547312 |
10 | 15120025560641 |
11 | 48aa4042837a1 |
12 | 1842441b74055 |
13 | 858a737b6291 |
14 | 3a3b55392a41 |
15 | 1b348e9b87cb |
hex | dc067c0a641 |
15120025560641 has 32 divisors (see below), whose sum is σ = 16576799247360. Its totient is φ = 13734753140736.
The previous prime is 15120025560517. The next prime is 15120025560671. The reversal of 15120025560641 is 14606552002151.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15120025560641 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15120025560595 and 15120025560604.
It is not an unprimeable number, because it can be changed into a prime (15120025560671) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 420344705 + ... + 420380673.
It is an arithmetic number, because the mean of its divisors is an integer number (518024976480).
Almost surely, 215120025560641 is an apocalyptic number.
It is an amenable number.
15120025560641 is a deficient number, since it is larger than the sum of its proper divisors (1456773686719).
15120025560641 is a wasteful number, since it uses less digits than its factorization.
15120025560641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43313.
The product of its (nonzero) digits is 72000, while the sum is 38.
Adding to 15120025560641 its reverse (14606552002151), we get a palindrome (29726577562792).
The spelling of 15120025560641 in words is "fifteen trillion, one hundred twenty billion, twenty-five million, five hundred sixty thousand, six hundred forty-one".
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