15120204762133 has 2 divisors, whose sum is σ = 15120204762134. Its totient is φ = 15120204762132.

The previous prime is 15120204762109. The next prime is 15120204762137. The reversal of 15120204762133 is 33126740202151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14345141100004 + 775063662129 = 3787498^2 + 880377^2 .

It is a cyclic number.

It is not a de Polignac number, because 15120204762133 - 2⁵ = 15120204762101 is a prime.

It is a super-2 number, since 2×15120204762133² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15120204762092 and 15120204762101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15120204762137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7560102381066 + 7560102381067.

It is an arithmetic number, because the mean of its divisors is an integer number (7560102381067).

Almost surely, 2^{15120204762133} is an apocalyptic number.

It is an amenable number.

15120204762133 is a deficient number, since it is larger than the sum of its proper divisors (1).

15120204762133 is an equidigital number, since it uses as much as digits as its factorization.

15120204762133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 37.

Adding to 15120204762133 its reverse (33126740202151), we get a palindrome (48246944964284).

The spelling of 15120204762133 in words is "fifteen trillion, one hundred twenty billion, two hundred four million, seven hundred sixty-two thousand, one hundred thirty-three".