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151224131 is a prime number
BaseRepresentation
bin10010000001101…
…11111101000011
3101112112222111202
421000313331003
5302203133011
623001131415
73514245452
oct1100677503
9345488452
10151224131
11783a8a23
1242789b6b
132543a146
1416126b99
15d42223b
hex9037f43

151224131 has 2 divisors, whose sum is σ = 151224132. Its totient is φ = 151224130.

The previous prime is 151224119. The next prime is 151224133. The reversal of 151224131 is 131422151.

151224131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-151224131 is a prime.

It is a super-2 number, since 2×1512241312 = 45737475593410322, which contains 22 as substring.

Together with 151224133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (151224133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75612065 + 75612066.

It is an arithmetic number, because the mean of its divisors is an integer number (75612066).

Almost surely, 2151224131 is an apocalyptic number.

151224131 is a deficient number, since it is larger than the sum of its proper divisors (1).

151224131 is an equidigital number, since it uses as much as digits as its factorization.

151224131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 240, while the sum is 20.

The square root of 151224131 is about 12297.3221068654. The cubic root of 151224131 is about 532.7707408230.

Adding to 151224131 its reverse (131422151), we get a palindrome (282646282).

The spelling of 151224131 in words is "one hundred fifty-one million, two hundred twenty-four thousand, one hundred thirty-one".