Base | Representation |
---|---|
bin | 1101110000010010011110… |
… | …1010000111001010110111 |
3 | 1222112202201221221020022122 |
4 | 3130010213222013022313 |
5 | 3440234401232400210 |
6 | 52055304541550155 |
7 | 3120422054125466 |
oct | 334044752071267 |
9 | 58482657836278 |
10 | 15123245200055 |
11 | 4900806720513 |
12 | 1842ba027535b |
13 | 859167840065 |
14 | 3a3d7cc109dd |
15 | 1b35cc495b55 |
hex | dc127a872b7 |
15123245200055 has 32 divisors (see below), whose sum is σ = 19045464940800. Its totient is φ = 11512825938432.
The previous prime is 15123245200033. The next prime is 15123245200057. The reversal of 15123245200055 is 55000254232151.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 15123245200055 - 212 = 15123245195959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15123245199988 and 15123245200024.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15123245200057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5195309 + ... + 7565561.
It is an arithmetic number, because the mean of its divisors is an integer number (595170779400).
Almost surely, 215123245200055 is an apocalyptic number.
15123245200055 is a deficient number, since it is larger than the sum of its proper divisors (3922219740745).
15123245200055 is a wasteful number, since it uses less digits than its factorization.
15123245200055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2370923.
The product of its (nonzero) digits is 60000, while the sum is 35.
The spelling of 15123245200055 in words is "fifteen trillion, one hundred twenty-three billion, two hundred forty-five million, two hundred thousand, fifty-five".
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