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15123314310242 = 27561657155121
BaseRepresentation
bin1101110000010010101111…
…0001101111110001100010
31222112202220202222101200012
43130010223301233301202
53440240021430411432
652055315451124522
73120423553425065
oct334045361576142
958482822871605
1015123314310242
114900841733a76
121842bbb443742
13859178c59868
143a3d880808dc
151b35d3597cb2
hexdc12bc6fc62

15123314310242 has 4 divisors (see below), whose sum is σ = 22684971465366. Its totient is φ = 7561657155120.

The previous prime is 15123314310241. The next prime is 15123314310257. The reversal of 15123314310242 is 24201341332151.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12124525956841 + 2998788353401 = 3482029^2 + 1731701^2 .

It is a junction number, because it is equal to n+sod(n) for n = 15123314310199 and 15123314310208.

It is not an unprimeable number, because it can be changed into a prime (15123314310241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3780828577559 + ... + 3780828577562.

Almost surely, 215123314310242 is an apocalyptic number.

15123314310242 is a deficient number, since it is larger than the sum of its proper divisors (7561657155124).

15123314310242 is an equidigital number, since it uses as much as digits as its factorization.

15123314310242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7561657155123.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 15123314310242 its reverse (24201341332151), we get a palindrome (39324655642393).

The spelling of 15123314310242 in words is "fifteen trillion, one hundred twenty-three billion, three hundred fourteen million, three hundred ten thousand, two hundred forty-two".

Divisors: 1 2 7561657155121 15123314310242