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151255126568543 is a prime number
BaseRepresentation
bin100010011001000011010100…
…000101101110111001011111
3201211112211220211112201222212
4202121003110011232321133
5124311130444400143133
61253405351302231035
743600552016436224
oct4231032405567137
9654484824481885
10151255126568543
1144215a3680a208
1214b6a30ba2547b
1366523b3038b3a
14294cb0408194b
15127475dab8148
hex8990d416ee5f

151255126568543 has 2 divisors, whose sum is σ = 151255126568544. Its totient is φ = 151255126568542.

The previous prime is 151255126568449. The next prime is 151255126568563. The reversal of 151255126568543 is 345865621552151.

151255126568543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 151255126568543 - 224 = 151255109791327 is a prime.

It is a super-2 number, since 2×1512551265685432 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (151255126568563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75627563284271 + 75627563284272.

It is an arithmetic number, because the mean of its divisors is an integer number (75627563284272).

Almost surely, 2151255126568543 is an apocalyptic number.

151255126568543 is a deficient number, since it is larger than the sum of its proper divisors (1).

151255126568543 is an equidigital number, since it uses as much as digits as its factorization.

151255126568543 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200000, while the sum is 59.

The spelling of 151255126568543 in words is "one hundred fifty-one trillion, two hundred fifty-five billion, one hundred twenty-six million, five hundred sixty-eight thousand, five hundred forty-three".