Base | Representation |
---|---|
bin | 1000110011100101001… |
… | …0111010000111111101 |
3 | 112110111022122000221222 |
4 | 2030321102322013331 |
5 | 4434312442111331 |
6 | 153255513003125 |
7 | 13633662150245 |
oct | 2147122720775 |
9 | 473438560858 |
10 | 151285113341 |
11 | 5918355889a |
12 | 253a10b34a5 |
13 | 1135c8a455b |
14 | 7472318b25 |
15 | 3e0682db7b |
hex | 23394ba1fd |
151285113341 has 2 divisors, whose sum is σ = 151285113342. Its totient is φ = 151285113340.
The previous prime is 151285113323. The next prime is 151285113361. The reversal of 151285113341 is 143311582151.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 150800188900 + 484924441 = 388330^2 + 22021^2 .
It is a cyclic number.
It is not a de Polignac number, because 151285113341 - 230 = 150211371517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151285113361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75642556670 + 75642556671.
It is an arithmetic number, because the mean of its divisors is an integer number (75642556671).
Almost surely, 2151285113341 is an apocalyptic number.
It is an amenable number.
151285113341 is a deficient number, since it is larger than the sum of its proper divisors (1).
151285113341 is an equidigital number, since it uses as much as digits as its factorization.
151285113341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 14400, while the sum is 35.
Adding to 151285113341 its reverse (143311582151), we get a palindrome (294596695492).
The spelling of 151285113341 in words is "one hundred fifty-one billion, two hundred eighty-five million, one hundred thirteen thousand, three hundred forty-one".
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