Base | Representation |
---|---|
bin | 11100001011101000… |
… | …11011001001111110 |
3 | 1110001102210100211021 |
4 | 32011310123021332 |
5 | 221441240424314 |
6 | 10541200414354 |
7 | 1043635666651 |
oct | 160564331176 |
9 | 43042710737 |
10 | 15130014334 |
11 | 6464553786 |
12 | 2b230173ba |
13 | 157176b206 |
14 | a375c9898 |
15 | 5d8447324 |
hex | 385d1b27e |
15130014334 has 4 divisors (see below), whose sum is σ = 22695021504. Its totient is φ = 7565007166.
The previous prime is 15130014323. The next prime is 15130014337. The reversal of 15130014334 is 43341003151.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43341003151 = 19 ⋅2281105429.
It is a junction number, because it is equal to n+sod(n) for n = 15130014299 and 15130014308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15130014337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3782503582 + ... + 3782503585.
It is an arithmetic number, because the mean of its divisors is an integer number (5673755376).
Almost surely, 215130014334 is an apocalyptic number.
15130014334 is a deficient number, since it is larger than the sum of its proper divisors (7565007170).
15130014334 is an equidigital number, since it uses as much as digits as its factorization.
15130014334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7565007169.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 15130014334 its reverse (43341003151), we get a palindrome (58471017485).
The spelling of 15130014334 in words is "fifteen billion, one hundred thirty million, fourteen thousand, three hundred thirty-four".
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