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1513146542263 is a prime number
BaseRepresentation
bin10110000001001110100…
…011111110100010110111
312100122200210011200101021
4112001032203332202313
5144242411003323023
63115044021442011
7214215116252056
oct26011643764267
95318623150337
101513146542263
115337a3859154
12205311870307
13ac8c5c763b5
145334566039d
15295615e635d
hex1604e8fe8b7

1513146542263 has 2 divisors, whose sum is σ = 1513146542264. Its totient is φ = 1513146542262.

The previous prime is 1513146542239. The next prime is 1513146542267. The reversal of 1513146542263 is 3622456413151.

It is a strong prime.

It is an emirp because it is prime and its reverse (3622456413151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1513146542263 - 213 = 1513146534071 is a prime.

It is a super-2 number, since 2×15131465422632 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1513146542267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 756573271131 + 756573271132.

It is an arithmetic number, because the mean of its divisors is an integer number (756573271132).

Almost surely, 21513146542263 is an apocalyptic number.

1513146542263 is a deficient number, since it is larger than the sum of its proper divisors (1).

1513146542263 is an equidigital number, since it uses as much as digits as its factorization.

1513146542263 is an evil number, because the sum of its binary digits is even.

The product of its digits is 518400, while the sum is 43.

The spelling of 1513146542263 in words is "one trillion, five hundred thirteen billion, one hundred forty-six million, five hundred forty-two thousand, two hundred sixty-three".