Base | Representation |
---|---|
bin | 101101000110011… |
… | …0101000010111001 |
3 | 10220110120020101221 |
4 | 1122030311002321 |
5 | 11044401444231 |
6 | 410055312041 |
7 | 52333641424 |
oct | 13214650271 |
9 | 3813506357 |
10 | 1513312441 |
11 | 707253043 |
12 | 36297b621 |
13 | 1b16a3764 |
14 | 104daa9bb |
15 | 8ccc8d11 |
hex | 5a3350b9 |
1513312441 has 2 divisors, whose sum is σ = 1513312442. Its totient is φ = 1513312440.
The previous prime is 1513312403. The next prime is 1513312447. The reversal of 1513312441 is 1442133151.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1276275625 + 237036816 = 35725^2 + 15396^2 .
It is an emirp because it is prime and its reverse (1442133151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1513312441 - 29 = 1513311929 is a prime.
It is a super-2 number, since 2×15133124412 = 4580229088170756962, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1513312447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 756656220 + 756656221.
It is an arithmetic number, because the mean of its divisors is an integer number (756656221).
Almost surely, 21513312441 is an apocalyptic number.
It is an amenable number.
1513312441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1513312441 is an equidigital number, since it uses as much as digits as its factorization.
1513312441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 25.
The square root of 1513312441 is about 38901.3167000810. The cubic root of 1513312441 is about 1148.0907048020.
Adding to 1513312441 its reverse (1442133151), we get a palindrome (2955445592).
The spelling of 1513312441 in words is "one billion, five hundred thirteen million, three hundred twelve thousand, four hundred forty-one".
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