Base | Representation |
---|---|
bin | 11100001100100101… |
… | …10010001110001011 |
3 | 1110001222202201020112 |
4 | 32012102302032023 |
5 | 222000310120011 |
6 | 10542043144535 |
7 | 1044063435311 |
oct | 160622621613 |
9 | 43058681215 |
10 | 15137973131 |
11 | 6468a9a2a6 |
12 | 2b2581514b |
13 | 15732c6968 |
14 | a3869c0b1 |
15 | 5d8eba58b |
hex | 3864b238b |
15137973131 has 2 divisors, whose sum is σ = 15137973132. Its totient is φ = 15137973130.
The previous prime is 15137973101. The next prime is 15137973167. The reversal of 15137973131 is 13137973151.
It is a weak prime.
It is an emirp because it is prime and its reverse (13137973151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15137973131 - 210 = 15137972107 is a prime.
It is a super-2 number, since 2×151379731312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15137973101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7568986565 + 7568986566.
It is an arithmetic number, because the mean of its divisors is an integer number (7568986566).
Almost surely, 215137973131 is an apocalyptic number.
15137973131 is a deficient number, since it is larger than the sum of its proper divisors (1).
15137973131 is an equidigital number, since it uses as much as digits as its factorization.
15137973131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 59535, while the sum is 41.
The spelling of 15137973131 in words is "fifteen billion, one hundred thirty-seven million, nine hundred seventy-three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •