Base | Representation |
---|---|
bin | 11000011110001010… |
… | …11000111110011111 |
3 | 1020220121102012001012 |
4 | 30033011120332133 |
5 | 203401310120101 |
6 | 10011400205435 |
7 | 643366633502 |
oct | 141705307637 |
9 | 36817365035 |
10 | 13137973151 |
11 | 5632052756 |
12 | 2667a6987b |
13 | 1314b4c614 |
14 | 8c8c03139 |
15 | 51d607bbb |
hex | 30f158f9f |
13137973151 has 2 divisors, whose sum is σ = 13137973152. Its totient is φ = 13137973150.
The previous prime is 13137973141. The next prime is 13137973159. The reversal of 13137973151 is 15137973131.
It is a strong prime.
It is an emirp because it is prime and its reverse (15137973131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13137973151 - 230 = 12064231327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13137973099 and 13137973108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13137973159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6568986575 + 6568986576.
It is an arithmetic number, because the mean of its divisors is an integer number (6568986576).
Almost surely, 213137973151 is an apocalyptic number.
13137973151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13137973151 is an equidigital number, since it uses as much as digits as its factorization.
13137973151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 59535, while the sum is 41.
The spelling of 13137973151 in words is "thirteen billion, one hundred thirty-seven million, nine hundred seventy-three thousand, one hundred fifty-one".
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