Base | Representation |
---|---|
bin | 11100001100110111… |
… | …10101010111101001 |
3 | 1110002011020020021102 |
4 | 32012123311113221 |
5 | 222001412022241 |
6 | 10542210051145 |
7 | 1044122545313 |
oct | 160633652751 |
9 | 43064206242 |
10 | 15140345321 |
11 | 646a36a592 |
12 | 2b26579ab5 |
13 | 157394761a |
14 | a38b187b3 |
15 | 5d92d839b |
hex | 3866f55e9 |
15140345321 has 2 divisors, whose sum is σ = 15140345322. Its totient is φ = 15140345320.
The previous prime is 15140345281. The next prime is 15140345323. The reversal of 15140345321 is 12354304151.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10560439696 + 4579905625 = 102764^2 + 67675^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15140345321 is a prime.
Together with 15140345323, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (15140345323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7570172660 + 7570172661.
It is an arithmetic number, because the mean of its divisors is an integer number (7570172661).
Almost surely, 215140345321 is an apocalyptic number.
It is an amenable number.
15140345321 is a deficient number, since it is larger than the sum of its proper divisors (1).
15140345321 is an equidigital number, since it uses as much as digits as its factorization.
15140345321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 15140345321 its reverse (12354304151), we get a palindrome (27494649472).
The spelling of 15140345321 in words is "fifteen billion, one hundred forty million, three hundred forty-five thousand, three hundred twenty-one".
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