Base | Representation |
---|---|
bin | 11100001100111000… |
… | …00111111011000001 |
3 | 1110002011101002111221 |
4 | 32012130013323001 |
5 | 222001421440223 |
6 | 10542211435041 |
7 | 1044123313003 |
oct | 160634077301 |
9 | 43064332457 |
10 | 15140421313 |
11 | 646a411696 |
12 | 2b265b5a81 |
13 | 15739730a4 |
14 | a38b38373 |
15 | 5d9300b5d |
hex | 386707ec1 |
15140421313 has 2 divisors, whose sum is σ = 15140421314. Its totient is φ = 15140421312.
The previous prime is 15140421271. The next prime is 15140421319. The reversal of 15140421313 is 31312404151.
15140421313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15113505969 + 26915344 = 122937^2 + 5188^2 .
It is a cyclic number.
It is not a de Polignac number, because 15140421313 - 217 = 15140290241 is a prime.
It is not a weakly prime, because it can be changed into another prime (15140421319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7570210656 + 7570210657.
It is an arithmetic number, because the mean of its divisors is an integer number (7570210657).
Almost surely, 215140421313 is an apocalyptic number.
It is an amenable number.
15140421313 is a deficient number, since it is larger than the sum of its proper divisors (1).
15140421313 is an equidigital number, since it uses as much as digits as its factorization.
15140421313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 15140421313 its reverse (31312404151), we get a palindrome (46452825464).
The spelling of 15140421313 in words is "fifteen billion, one hundred forty million, four hundred twenty-one thousand, three hundred thirteen".
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