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1514381413 is a prime number
BaseRepresentation
bin101101001000011…
…1010000001100101
310220112120112202111
41122100322001211
511100140201123
6410134241021
752346013106
oct13220720145
93815515674
101514381413
11707913196
123631b6171
131b198919c
141051a83ad
158ce3a90d
hex5a43a065

1514381413 has 2 divisors, whose sum is σ = 1514381414. Its totient is φ = 1514381412.

The previous prime is 1514381347. The next prime is 1514381431. The reversal of 1514381413 is 3141834151.

Together with next prime (1514381431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1326197889 + 188183524 = 36417^2 + 13718^2 .

It is an emirp because it is prime and its reverse (3141834151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1514381413 - 213 = 1514373221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1514381483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 757190706 + 757190707.

It is an arithmetic number, because the mean of its divisors is an integer number (757190707).

Almost surely, 21514381413 is an apocalyptic number.

It is an amenable number.

1514381413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1514381413 is an equidigital number, since it uses as much as digits as its factorization.

1514381413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5760, while the sum is 31.

The square root of 1514381413 is about 38915.0538095478. The cubic root of 1514381413 is about 1148.3609701975.

The spelling of 1514381413 in words is "one billion, five hundred fourteen million, three hundred eighty-one thousand, four hundred thirteen".