Base | Representation |
---|---|
bin | 1101110001100100000010… |
… | …1101101110000000011111 |
3 | 1222121212020212122021012221 |
4 | 3130121000231232000133 |
5 | 3441114221421144242 |
6 | 52113325332210211 |
7 | 3122125461302113 |
oct | 334310055560037 |
9 | 58555225567187 |
10 | 15145140412447 |
11 | 490a021a25671 |
12 | 1847290a69967 |
13 | 85b246a63336 |
14 | 3a5058ab5743 |
15 | 1b3e5e7c6167 |
hex | dc640b6e01f |
15145140412447 has 2 divisors, whose sum is σ = 15145140412448. Its totient is φ = 15145140412446.
The previous prime is 15145140412429. The next prime is 15145140412471. The reversal of 15145140412447 is 74421404154151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15145140412447 - 215 = 15145140379679 is a prime.
It is a super-2 number, since 2×151451404124472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15145140412547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7572570206223 + 7572570206224.
It is an arithmetic number, because the mean of its divisors is an integer number (7572570206224).
Almost surely, 215145140412447 is an apocalyptic number.
15145140412447 is a deficient number, since it is larger than the sum of its proper divisors (1).
15145140412447 is an equidigital number, since it uses as much as digits as its factorization.
15145140412447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 358400, while the sum is 43.
Adding to 15145140412447 its reverse (74421404154151), we get a palindrome (89566544566598).
The spelling of 15145140412447 in words is "fifteen trillion, one hundred forty-five billion, one hundred forty million, four hundred twelve thousand, four hundred forty-seven".
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