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15145140412447 is a prime number
BaseRepresentation
bin1101110001100100000010…
…1101101110000000011111
31222121212020212122021012221
43130121000231232000133
53441114221421144242
652113325332210211
73122125461302113
oct334310055560037
958555225567187
1015145140412447
11490a021a25671
121847290a69967
1385b246a63336
143a5058ab5743
151b3e5e7c6167
hexdc640b6e01f

15145140412447 has 2 divisors, whose sum is σ = 15145140412448. Its totient is φ = 15145140412446.

The previous prime is 15145140412429. The next prime is 15145140412471. The reversal of 15145140412447 is 74421404154151.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 15145140412447 - 215 = 15145140379679 is a prime.

It is a super-2 number, since 2×151451404124472 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15145140412547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7572570206223 + 7572570206224.

It is an arithmetic number, because the mean of its divisors is an integer number (7572570206224).

Almost surely, 215145140412447 is an apocalyptic number.

15145140412447 is a deficient number, since it is larger than the sum of its proper divisors (1).

15145140412447 is an equidigital number, since it uses as much as digits as its factorization.

15145140412447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 358400, while the sum is 43.

Adding to 15145140412447 its reverse (74421404154151), we get a palindrome (89566544566598).

The spelling of 15145140412447 in words is "fifteen trillion, one hundred forty-five billion, one hundred forty million, four hundred twelve thousand, four hundred forty-seven".