Base | Representation |
---|---|
bin | 1101110001100100000010… |
… | …1101101110000001010011 |
3 | 1222121212020212122021021212 |
4 | 3130121000231232001103 |
5 | 3441114221421144444 |
6 | 52113325332210335 |
7 | 3122125461302216 |
oct | 334310055560123 |
9 | 58555225567255 |
10 | 15145140412499 |
11 | 490a021a25709 |
12 | 1847290a699ab |
13 | 85b246a63376 |
14 | 3a5058ab577d |
15 | 1b3e5e7c619e |
hex | dc640b6e053 |
15145140412499 has 2 divisors, whose sum is σ = 15145140412500. Its totient is φ = 15145140412498.
The previous prime is 15145140412471. The next prime is 15145140412511. The reversal of 15145140412499 is 99421404154151.
It is a strong prime.
It is an emirp because it is prime and its reverse (99421404154151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15145140412499 - 28 = 15145140412243 is a prime.
It is a super-2 number, since 2×151451404124992 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15145140412429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7572570206249 + 7572570206250.
It is an arithmetic number, because the mean of its divisors is an integer number (7572570206250).
Almost surely, 215145140412499 is an apocalyptic number.
15145140412499 is a deficient number, since it is larger than the sum of its proper divisors (1).
15145140412499 is an equidigital number, since it uses as much as digits as its factorization.
15145140412499 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1036800, while the sum is 50.
The spelling of 15145140412499 in words is "fifteen trillion, one hundred forty-five billion, one hundred forty million, four hundred twelve thousand, four hundred ninety-nine".
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