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99421404154151 is a prime number
BaseRepresentation
bin10110100110110001011001…
…011110100100100100100111
3111001000121000121011011102112
4112212301121132210210213
5101012410013430413101
6551241321301431235
726640650035455062
oct2646613136444447
9431017017134375
1099421404154151
1129751420809482
12b19864b10b51b
134362523a67911
141a7a0435278d9
15b762a3ad36bb
hex5a6c597a4927

99421404154151 has 2 divisors, whose sum is σ = 99421404154152. Its totient is φ = 99421404154150.

The previous prime is 99421404154049. The next prime is 99421404154153. The reversal of 99421404154151 is 15145140412499.

It is a strong prime.

It is an emirp because it is prime and its reverse (15145140412499) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99421404154151 - 214 = 99421404137767 is a prime.

Together with 99421404154153, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 99421404154151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (99421404154153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49710702077075 + 49710702077076.

It is an arithmetic number, because the mean of its divisors is an integer number (49710702077076).

Almost surely, 299421404154151 is an apocalyptic number.

99421404154151 is a deficient number, since it is larger than the sum of its proper divisors (1).

99421404154151 is an equidigital number, since it uses as much as digits as its factorization.

99421404154151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 50.

The spelling of 99421404154151 in words is "ninety-nine trillion, four hundred twenty-one billion, four hundred four million, one hundred fifty-four thousand, one hundred fifty-one".