Base | Representation |
---|---|
bin | 1000110100010110011… |
… | …0001110101010110111 |
3 | 112111000200222210211221 |
4 | 2031011212032222313 |
5 | 4440223311123243 |
6 | 153332204411211 |
7 | 13642046354551 |
oct | 2150546165267 |
9 | 474020883757 |
10 | 151491504823 |
11 | 5927a00686a |
12 | 2543a246b07 |
13 | 11393588aa9 |
14 | 74918c24d1 |
15 | 3e199ebbed |
hex | 234598eab7 |
151491504823 has 2 divisors, whose sum is σ = 151491504824. Its totient is φ = 151491504822.
The previous prime is 151491504817. The next prime is 151491504859. The reversal of 151491504823 is 328405194151.
It is a weak prime.
It is an emirp because it is prime and its reverse (328405194151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 151491504823 - 213 = 151491496631 is a prime.
It is a super-2 number, since 2×1514915048232 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 151491504823.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151491504803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75745752411 + 75745752412.
It is an arithmetic number, because the mean of its divisors is an integer number (75745752412).
Almost surely, 2151491504823 is an apocalyptic number.
151491504823 is a deficient number, since it is larger than the sum of its proper divisors (1).
151491504823 is an equidigital number, since it uses as much as digits as its factorization.
151491504823 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 43.
Adding to 151491504823 its reverse (328405194151), we get a palindrome (479896698974).
The spelling of 151491504823 in words is "one hundred fifty-one billion, four hundred ninety-one million, five hundred four thousand, eight hundred twenty-three".
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