Base | Representation |
---|---|
bin | 10110000101001101010… |
… | …110111101000101011101 |
3 | 12101001201200220210221211 |
4 | 112011031112331011131 |
5 | 144330134324142433 |
6 | 3121032125024421 |
7 | 214426054251403 |
oct | 26051526750535 |
9 | 5331650823854 |
10 | 1517421318493 |
11 | 535597858873 |
12 | 2061053b5111 |
13 | b01277a38a2 |
14 | 5362d29d473 |
15 | 29711a468cd |
hex | 1614d5bd15d |
1517421318493 has 2 divisors, whose sum is σ = 1517421318494. Its totient is φ = 1517421318492.
The previous prime is 1517421318473. The next prime is 1517421318557. The reversal of 1517421318493 is 3948131247151.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1344342853764 + 173078464729 = 1159458^2 + 416027^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1517421318493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1517421318463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 758710659246 + 758710659247.
It is an arithmetic number, because the mean of its divisors is an integer number (758710659247).
Almost surely, 21517421318493 is an apocalyptic number.
It is an amenable number.
1517421318493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1517421318493 is an equidigital number, since it uses as much as digits as its factorization.
1517421318493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 725760, while the sum is 49.
The spelling of 1517421318493 in words is "one trillion, five hundred seventeen billion, four hundred twenty-one million, three hundred eighteen thousand, four hundred ninety-three".
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