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152000117 is a prime number
BaseRepresentation
bin10010000111101…
…01011001110101
3101121000101221222
421003311121311
5302403000432
623025520125
73523660013
oct1103653165
9347011858
10152000117
1178888a35
1242aa3045
132564c3c9
14162898b3
15d527112
hex90f5675

152000117 has 2 divisors, whose sum is σ = 152000118. Its totient is φ = 152000116.

The previous prime is 152000071. The next prime is 152000183. The reversal of 152000117 is 711000251.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 143185156 + 8814961 = 11966^2 + 2969^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-152000117 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 152000095 and 152000104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152000617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76000058 + 76000059.

It is an arithmetic number, because the mean of its divisors is an integer number (76000059).

Almost surely, 2152000117 is an apocalyptic number.

It is an amenable number.

152000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

152000117 is an equidigital number, since it uses as much as digits as its factorization.

152000117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 70, while the sum is 17.

The square root of 152000117 is about 12328.8327509136. The cubic root of 152000117 is about 533.6804666755.

Adding to 152000117 its reverse (711000251), we get a palindrome (863000368).

The spelling of 152000117 in words is "one hundred fifty-two million, one hundred seventeen", and thus it is an aban number.