Base | Representation |
---|---|
bin | 10110000111101111011… |
… | …110001001010000001011 |
3 | 12101022202020200122200221 |
4 | 112013233132021100023 |
5 | 144401222111043311 |
6 | 3122202043410511 |
7 | 214553341154452 |
oct | 26075736112013 |
9 | 5338666618627 |
10 | 1520141112331 |
11 | 536763034176 |
12 | 206744223a37 |
13 | b046c0ca95a |
14 | 5380a5a5b99 |
15 | 298206db671 |
hex | 161ef78940b |
1520141112331 has 2 divisors, whose sum is σ = 1520141112332. Its totient is φ = 1520141112330.
The previous prime is 1520141112311. The next prime is 1520141112337. The reversal of 1520141112331 is 1332111410251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1520141112331 - 221 = 1520139015179 is a prime.
It is a super-2 number, since 2×15201411123312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1520141112296 and 1520141112305.
It is not a weakly prime, because it can be changed into another prime (1520141112337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760070556165 + 760070556166.
It is an arithmetic number, because the mean of its divisors is an integer number (760070556166).
Almost surely, 21520141112331 is an apocalyptic number.
1520141112331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1520141112331 is an equidigital number, since it uses as much as digits as its factorization.
1520141112331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 1520141112331 its reverse (1332111410251), we get a palindrome (2852252522582).
The spelling of 1520141112331 in words is "one trillion, five hundred twenty billion, one hundred forty-one million, one hundred twelve thousand, three hundred thirty-one".
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