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152015117 is a prime number
BaseRepresentation
bin10010000111110…
…01000100001101
3101121001011112112
421003321010031
5302403440432
623030113405
73524051522
oct1103710415
9347034475
10152015117
1178899231
1242aab865
1325656197
1416291149
15d52b7b2
hex90f910d

152015117 has 2 divisors, whose sum is σ = 152015118. Its totient is φ = 152015116.

The previous prime is 152015053. The next prime is 152015147. The reversal of 152015117 is 711510251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85119076 + 66896041 = 9226^2 + 8179^2 .

It is a cyclic number.

It is not a de Polignac number, because 152015117 - 26 = 152015053 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 152015092 and 152015101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152015147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76007558 + 76007559.

It is an arithmetic number, because the mean of its divisors is an integer number (76007559).

Almost surely, 2152015117 is an apocalyptic number.

It is an amenable number.

152015117 is a deficient number, since it is larger than the sum of its proper divisors (1).

152015117 is an equidigital number, since it uses as much as digits as its factorization.

152015117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 350, while the sum is 23.

The square root of 152015117 is about 12329.4410660013. The cubic root of 152015117 is about 533.6980213630.

Adding to 152015117 its reverse (711510251), we get a palindrome (863525368).

The spelling of 152015117 in words is "one hundred fifty-two million, fifteen thousand, one hundred seventeen".