Base | Representation |
---|---|
bin | 10110000111110011101… |
… | …100111111011011100111 |
3 | 12101022221012021212111001 |
4 | 112013303230333123213 |
5 | 144401343300110002 |
6 | 3122213101254131 |
7 | 214555162520041 |
oct | 26076354773347 |
9 | 5338835255431 |
10 | 1520212113127 |
11 | 53679a119114 |
12 | 206763b64347 |
13 | b0480a29b66 |
14 | 53815ba8a91 |
15 | 29826a63a87 |
hex | 161f3b3f6e7 |
1520212113127 has 2 divisors, whose sum is σ = 1520212113128. Its totient is φ = 1520212113126.
The previous prime is 1520212113103. The next prime is 1520212113137. The reversal of 1520212113127 is 7213112120251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1520212113127 - 27 = 1520212112999 is a prime.
It is a super-2 number, since 2×15202121131272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1520212113095 and 1520212113104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1520212113137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760106056563 + 760106056564.
It is an arithmetic number, because the mean of its divisors is an integer number (760106056564).
Almost surely, 21520212113127 is an apocalyptic number.
1520212113127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1520212113127 is an equidigital number, since it uses as much as digits as its factorization.
1520212113127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1680, while the sum is 28.
Adding to 1520212113127 its reverse (7213112120251), we get a palindrome (8733324233378).
The spelling of 1520212113127 in words is "one trillion, five hundred twenty billion, two hundred twelve million, one hundred thirteen thousand, one hundred twenty-seven".
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