Base | Representation |
---|---|
bin | 10110000111110100010… |
… | …111101011110100110011 |
3 | 12101022221222100110212021 |
4 | 112013310113223310303 |
5 | 144401404131230021 |
6 | 3122214141212311 |
7 | 214555356612325 |
oct | 26076427536463 |
9 | 5338858313767 |
10 | 1520223305011 |
11 | 5367a5472804 |
12 | 206767861097 |
13 | b0483148088 |
14 | 5381747d615 |
15 | 29827a24c41 |
hex | 161f45ebd33 |
1520223305011 has 2 divisors, whose sum is σ = 1520223305012. Its totient is φ = 1520223305010.
The previous prime is 1520223304997. The next prime is 1520223305017. The reversal of 1520223305011 is 1105033220251.
It is a strong prime.
It is an emirp because it is prime and its reverse (1105033220251) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1520223305011 - 25 = 1520223304979 is a prime.
It is a super-2 number, since 2×15202233050112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1520223305017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 760111652505 + 760111652506.
It is an arithmetic number, because the mean of its divisors is an integer number (760111652506).
Almost surely, 21520223305011 is an apocalyptic number.
1520223305011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1520223305011 is an equidigital number, since it uses as much as digits as its factorization.
1520223305011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 1520223305011 its reverse (1105033220251), we get a palindrome (2625256525262).
The spelling of 1520223305011 in words is "one trillion, five hundred twenty billion, two hundred twenty-three million, three hundred five thousand, eleven".
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