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152032754681 is a prime number
BaseRepresentation
bin1000110110010111011…
…0111011101111111001
3112112102102110011001222
42031211312323233321
54442330341122211
6153502021321425
713661341043513
oct2154566735771
9475372404058
10152032754681
11595275878a5
122556b566275
131144b754592
147503734bb3
153e4c2b21db
hex2365dbbbf9

152032754681 has 2 divisors, whose sum is σ = 152032754682. Its totient is φ = 152032754680.

The previous prime is 152032754663. The next prime is 152032754683. The reversal of 152032754681 is 186457230251.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99174606400 + 52858148281 = 314920^2 + 229909^2 .

It is a cyclic number.

It is not a de Polignac number, because 152032754681 - 210 = 152032753657 is a prime.

It is a super-2 number, since 2×1520327546812 (a number of 23 digits) contains 22 as substring.

Together with 152032754683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (152032754683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76016377340 + 76016377341.

It is an arithmetic number, because the mean of its divisors is an integer number (76016377341).

Almost surely, 2152032754681 is an apocalyptic number.

It is an amenable number.

152032754681 is a deficient number, since it is larger than the sum of its proper divisors (1).

152032754681 is an equidigital number, since it uses as much as digits as its factorization.

152032754681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 403200, while the sum is 44.

The spelling of 152032754681 in words is "one hundred fifty-two billion, thirty-two million, seven hundred fifty-four thousand, six hundred eighty-one".