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152113133 is a prime number
BaseRepresentation
bin10010001000100…
…00111111101101
3101121020010222202
421010100333231
5302420110013
623032151245
73524640344
oct1104207755
9347203882
10152113133
1178955937
1242b38525
132568b993
14162b8b5b
15d54a858
hex9110fed

152113133 has 2 divisors, whose sum is σ = 152113134. Its totient is φ = 152113132.

The previous prime is 152113109. The next prime is 152113141. The reversal of 152113133 is 331311251.

152113133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115304644 + 36808489 = 10738^2 + 6067^2 .

It is a cyclic number.

It is not a de Polignac number, because 152113133 - 210 = 152112109 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152413133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76056566 + 76056567.

It is an arithmetic number, because the mean of its divisors is an integer number (76056567).

Almost surely, 2152113133 is an apocalyptic number.

It is an amenable number.

152113133 is a deficient number, since it is larger than the sum of its proper divisors (1).

152113133 is an equidigital number, since it uses as much as digits as its factorization.

152113133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 270, while the sum is 20.

The square root of 152113133 is about 12333.4153015294. The cubic root of 152113133 is about 533.8127022960.

Adding to 152113133 its reverse (331311251), we get a palindrome (483424384).

The spelling of 152113133 in words is "one hundred fifty-two million, one hundred thirteen thousand, one hundred thirty-three".