Search a number
-
+
15213136507 is a prime number
BaseRepresentation
bin11100010101100011…
…00000101001111011
31110021020012102000021
432022301200221323
5222124030332012
610553330151311
71045665345442
oct161261405173
943236172007
1015213136507
1164a7467698
122b46a22537
131585a5272a
14a44665d59
155e08b6007
hex38ac60a7b

15213136507 has 2 divisors, whose sum is σ = 15213136508. Its totient is φ = 15213136506.

The previous prime is 15213136459. The next prime is 15213136517. The reversal of 15213136507 is 70563131251.

15213136507 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15213136507 is a prime.

It is a super-2 number, since 2×152131365072 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15213136517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7606568253 + 7606568254.

It is an arithmetic number, because the mean of its divisors is an integer number (7606568254).

Almost surely, 215213136507 is an apocalyptic number.

15213136507 is a deficient number, since it is larger than the sum of its proper divisors (1).

15213136507 is an equidigital number, since it uses as much as digits as its factorization.

15213136507 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18900, while the sum is 34.

Adding to 15213136507 its reverse (70563131251), we get a palindrome (85776267758).

The spelling of 15213136507 in words is "fifteen billion, two hundred thirteen million, one hundred thirty-six thousand, five hundred seven".