Base | Representation |
---|---|
bin | 1101110101100100111110… |
… | …1000110001110011000110 |
3 | 1222212110021111120010221102 |
4 | 3131121033220301303012 |
5 | 3443231444211032410 |
6 | 52205133223220102 |
7 | 3130116556254161 |
oct | 335311750616306 |
9 | 58773244503842 |
10 | 15214110252230 |
11 | 49362a467405a |
12 | 185871a8a7632 |
13 | 8648b8940916 |
14 | 3a851c96cad8 |
15 | 1b5b497492a5 |
hex | dd64fa31cc6 |
15214110252230 has 8 divisors (see below), whose sum is σ = 27385398454032. Its totient is φ = 6085644100888.
The previous prime is 15214110252221. The next prime is 15214110252293. The reversal of 15214110252230 is 3225201141251.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 15214110252193 and 15214110252202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 760705512602 + ... + 760705512621.
It is an arithmetic number, because the mean of its divisors is an integer number (3423174806754).
Almost surely, 215214110252230 is an apocalyptic number.
15214110252230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
15214110252230 is a deficient number, since it is larger than the sum of its proper divisors (12171288201802).
15214110252230 is a wasteful number, since it uses less digits than its factorization.
15214110252230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1521411025230.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 15214110252230 its reverse (3225201141251), we get a palindrome (18439311393481).
The spelling of 15214110252230 in words is "fifteen trillion, two hundred fourteen billion, one hundred ten million, two hundred fifty-two thousand, two hundred thirty".
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