Base | Representation |
---|---|
bin | 1000110110110001100… |
… | …1100111101000100111 |
3 | 112112201001222022221011 |
4 | 2031230121213220213 |
5 | 4443041440320011 |
6 | 153520542003051 |
7 | 13664143000636 |
oct | 2155431475047 |
9 | 475631868834 |
10 | 152142510631 |
11 | 595835320a1 |
12 | 255a0276487 |
13 | 11468402827 |
14 | 751414551d |
15 | 3e56c42621 |
hex | 236c667a27 |
152142510631 has 2 divisors, whose sum is σ = 152142510632. Its totient is φ = 152142510630.
The previous prime is 152142510547. The next prime is 152142510691. The reversal of 152142510631 is 136015241251.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 152142510631 - 219 = 152141986343 is a prime.
It is a super-2 number, since 2×1521425106312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 152142510593 and 152142510602.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (152142510691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76071255315 + 76071255316.
It is an arithmetic number, because the mean of its divisors is an integer number (76071255316).
Almost surely, 2152142510631 is an apocalyptic number.
152142510631 is a deficient number, since it is larger than the sum of its proper divisors (1).
152142510631 is an equidigital number, since it uses as much as digits as its factorization.
152142510631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 152142510631 its reverse (136015241251), we get a palindrome (288157751882).
The spelling of 152142510631 in words is "one hundred fifty-two billion, one hundred forty-two million, five hundred ten thousand, six hundred thirty-one".
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