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152142510631 is a prime number
BaseRepresentation
bin1000110110110001100…
…1100111101000100111
3112112201001222022221011
42031230121213220213
54443041440320011
6153520542003051
713664143000636
oct2155431475047
9475631868834
10152142510631
11595835320a1
12255a0276487
1311468402827
14751414551d
153e56c42621
hex236c667a27

152142510631 has 2 divisors, whose sum is σ = 152142510632. Its totient is φ = 152142510630.

The previous prime is 152142510547. The next prime is 152142510691. The reversal of 152142510631 is 136015241251.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 152142510631 - 219 = 152141986343 is a prime.

It is a super-2 number, since 2×1521425106312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 152142510593 and 152142510602.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (152142510691) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76071255315 + 76071255316.

It is an arithmetic number, because the mean of its divisors is an integer number (76071255316).

Almost surely, 2152142510631 is an apocalyptic number.

152142510631 is a deficient number, since it is larger than the sum of its proper divisors (1).

152142510631 is an equidigital number, since it uses as much as digits as its factorization.

152142510631 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 152142510631 its reverse (136015241251), we get a palindrome (288157751882).

The spelling of 152142510631 in words is "one hundred fifty-two billion, one hundred forty-two million, five hundred ten thousand, six hundred thirty-one".